Find the force of interaction - 2

Find the electrostatic force of interaction between two parallel non conducting wires each of length ll , charge density per unit length λ\lambda, and separated by a distance dd.

Give your answer as the value of this force in  Newtons \text{ Newtons } using λ=10μC/ m \lambda = 10 \mu \text{C/ m}, l=1m l = 1 \text{m} ,  d = 1m ,14πϵ0=9×109 N m2/C2\text{ d = 1m }, \frac{1}{4 \pi \epsilon_{0} } = 9 \times 10^9\text{ N } m^2/ C^2

Note:

The wires completely face each other (like if their equations were 0xL,y,z=00 \leq x \leq L, y,z= 0 and 0xL,y=d,z=00 \leq x \leq L, y= d, z=0)

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