Find the force of interaction - 2

Find the electrostatic force of interaction between two parallel non conducting wires each of length $l$ , charge density per unit length $\lambda$, and separated by a distance $d$.

Give your answer as the value of this force in $\text{ Newtons }$ using $\lambda = 10 \mu \text{C/ m}$, $l = 1 \text{m}$, $\text{ d = 1m }, \frac{1}{4 \pi \epsilon_{0} } = 9 \times 10^9\text{ N } m^2/ C^2$

Note:

The wires completely face each other (like if their equations were $0 \leq x \leq L, y,z= 0$ and $0 \leq x \leq L, y= d, z=0$)