# Find the force of interaction - 2

**Electricity and Magnetism**Level 3

Find the **electrostatic force of interaction** between two parallel non conducting wires each of length \(l\) , charge density per unit length \(\lambda\), and separated by a distance \(d\).

Give your answer as the value of this force in \(\text{ Newtons }\) using \( \lambda = 10 \mu \text{C/ m}\), \( l = 1 \text{m} \), \(\text{ d = 1m }, \frac{1}{4 \pi \epsilon_{0} } = 9 \times 10^9\text{ N } m^2/ C^2 \)

**Note**:

The wires completely face each other (like if their equations were \(0 \leq x \leq L, y,z= 0\) and \(0 \leq x \leq L, y= d, z=0\))

**Your answer seems reasonable.**Find out if you're right!

**That seems reasonable.**Find out if you're right!

Already have an account? Log in here.