Quadrilateral \(ABCD\) is a square. \(\angle PAB = \angle PBA = 15^\circ\).

Find the geometric mean of the angles of \(\Delta PCD\) taken **in degrees**.

**Details & Assumptions :** Geometric Mean of numbers \(a_1, a_2, \dots, a_n\) is \(\sqrt[n]{a_1 \cdot a_2 \cdot a_3 \dots a_n}\).

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