The given arithmetic progression where a= initial value, d= common difference, n= nth term tn=a+(n-1)d tn=8+(n-1)3.5

The given geometric progression where a=initial value, r=common ratio, n=nth term tn=a*r^n-1 tn=10 * 1.1^n-1

Hint: Try finding through the use of rearranging, logarithms and the quadratic formula.

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