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Suppose that yyy satisfies the equation y′+ytanx=secx.y'+y\tan x=\sec x.y′+ytanx=secx. y(π4)=12.y\left (\dfrac{\pi}{4}\right) = \dfrac{1}{\sqrt{2}}. y(4π)=21.
What is the value of y(π2)?y\left (\dfrac{\pi}{2}\right)?y(2π)?
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