# Foolish \(\alpha \) Particle in Variable Magnetic Field

**Electricity and Magnetism**Level 5

**variable**magnetic field exist in \(XYZ\) plane only in 1st quadrant, such that its magnitude is varying with distance \(x\) \((B={ B }_{ 0 }x)\) and direction in positive \(Z\)-axis.

Now an \(\alpha\)-particle of mass \(m\) and charge \(q\) enters in this magnetic field at origin with velocity \({V}_{0}\) and direction in positive \(X\)-axis.

Then find the **radius of curvature** of trajectory of particle at the instant when the particle displaced **maximum distance** in \(X\)-direction

**Details and assumptions**

1)\({ B }_{ 0 }=1.67\times { 10 }^{ -27 }T\)

2)\({ V }_{ 0 }=1.28\times { 10 }^{ -18 }m/s\)

3)\({ m }_{ \alpha }=6.68\times { 10 }^{ -27 }Kg\)

4)\({ q }_{ \alpha }=3.2\times { 10 }^{ -19 } C\)

###### This is Part of set Foolish Things

**Your answer seems reasonable.**Find out if you're right!

**That seems reasonable.**Find out if you're right!

Already have an account? Log in here.