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(i+3−i+3)2020+(i−3i+3)2017+1= ?\large \left(\dfrac{i + \sqrt 3}{- i + \sqrt 3}\right)^{2020} + \left(\dfrac{i - \sqrt 3}{i + \sqrt 3}\right)^{2017} + 1 = \, ? (−i+3i+3)2020+(i+3i−3)2017+1=?
Clarification: i=−1i=\sqrt{-1} i=−1 denotes the imaginary unit.
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