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Simplify:
1(b−c)(a2+ac−b2−bc)+1(c−a)(b2+ab−c2−ac)+1(a−b)(c2+bc−a2−ab) \frac{1}{(b-c)(a^2+ac-b^2-bc)} +\frac{1}{(c-a)(b^2+ab-c^2-ac)}+\frac{1}{(a-b)(c^2+bc-a^2-ab)} (b−c)(a2+ac−b2−bc)1+(c−a)(b2+ab−c2−ac)1+(a−b)(c2+bc−a2−ab)1
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