Fun with optics!

Water (with refractive index \(\frac43\) ) in a tank is 18 cm. Oil of refractive index \( \frac74\) lies on water making a convex surface of radius of curvature \(R = 6\text{ cm}\). Consider oil to act as a thin lens. An object \(S\) is placed \(24\text{ cm}\) above water surface. The location of its image is at \( X \text{ cm}\) above the bottom of the tank. What is the value of \(X\)?

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