# Function Sums to One

Level pendingA function \(f:\{1, 2, \cdots , 2014\} \rightarrow \mathbb{R^+} \) satisfies the following relation.

\[\sum \limits_{i=1; \ i \neq j}^{2014} f(i) f(j) = 1 \quad \forall \ j \in \{1, 2, \cdots , 2014 \} \] The sum of all possible values of \(f(2014)\) is \(k\). Find \( \dfrac{1}{k^2}\).

**Details and assumptions**

The range of \(f\) is \(\mathbb{R^+},\) i.e. \(f(x)\) is always positive.

If no such functions exist, \(k=0\).

If \(f(2014)\) can take only one value, \(k\) equals the only possible value of \(f(2014)\).

###### This problem appeared in the Proofathon Algebra contest, and was posed by Paramjit Singh.

**Your answer seems reasonable.**Find out if you're right!

**That seems reasonable.**Find out if you're right!

Already have an account? Log in here.