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f(x)={−x+1, x≤0−(x−1)2,x≥1\large f(x)=\begin{cases} -x+1, \quad \ \ \ \ x \leq 0 \\ -(x-1)^2, \quad x \geq 1 \end{cases}f(x)=⎩⎨⎧−x+1, x≤0−(x−1)2,x≥1
Define the piecewise function of f(x)f(x)f(x) above, find the number of solution(s) of the equation f(x)−f−1(x)=0f(x)-f^{-1}(x)=0f(x)−f−1(x)=0.
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