Function(function)

Algebra Level 2

Let \(f(x)\) be defined on \([0,1]\) by the rule \[f(x)=\begin{cases}x & \mbox{if }x\in\mathbb{Q} \\ 1-x & \mbox{if }x\notin\mathbb{Q}\end{cases}\] Then for all \(x\in[0,1]\), \(f(f(x))\) is

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