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f(11996)+f(21996)+f(31996)+…+f(19951996)\large f\left(\frac{1}{1996}\right)+f\left(\frac{2}{1996}\right)+f\left(\frac{3}{1996}\right)+ \ldots+f\left(\frac{1995}{1996}\right)f(19961)+f(19962)+f(19963)+…+f(19961995)
Find the value of the summation above if f(x)=9x9x+3f\left( x \right) =\frac { { 9 }^{ x } }{ { 9 }^{ x }+3 }f(x)=9x+39x.
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