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True or False?
Consider the function f(x)=1x f(x) = \frac{1}{x} f(x)=x1. Since f′(x)=−1x2<0f'(x) = -\frac{1}{x^{2}} < 0f′(x)=−x21<0, f(x)f(x) f(x) is a decreasing function in its domain (−∞,0)∪(0,∞)(-\infty, 0) \cup (0, \infty)(−∞,0)∪(0,∞).
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