Taken on the sides \(AB\) and \(BC\) of \(\triangle ABC\) are points \(K\) and \(P\) such that \(AK:BK=1:2\) and \(CP:BP=2:1\). The striaght lines \(AP\) and \(CK\) intersect at point \(E\). Find the area of \(\triangle ABC\) if it is known that the area of \(\triangle BEC\) is equal to \(4\text{ cm}^2\).

Give your answer in \(\text{cm}^{2}\).

×

Problem Loading...

Note Loading...

Set Loading...