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Similar Triangle Challenge

Geometry Level 1

$\overline{AB}$ is parallel to $\overline{DE}$ , $AC=5,$ and $CD=13.$

If the area of $\triangle ABC$ is $11,$ what is the area of $\triangle CDE$ ?

\frac{55}{13}

\frac{275}{169}

\frac{1859}{25}

\frac{143}{5}

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by Perry Ellis

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