Triangle \(ABC\) is isosceles, with \(AB=AC\) and altitude \(AM=11.\) Suppose that there is a point \(D\) on \(\overline{AM}\) with \(AD=10\) and \(\angle BDC=3\angle BAC.\) Then the perimeter of \(\triangle ABC\) may be written in the form \(a+\sqrt{b},\) where \(a\) and \(b\) are integers. Find \(a+b.\)

×

Problem Loading...

Note Loading...

Set Loading...