Getting back to the old things #1

One mole of a mono atomic ideal gas undergoes a thermodynamic process such that \(V^3/T^2\)= constant. Then:

  1. Work done by gas is 200R when temperature of gas is raised by 300K.
  2. Specific heat of gas in the process is \(13R/6\).
  3. Work done by gas is 300R when temperature of gas is raised by 600K.
  4. The specific heat of the gas in the process is \(21R/4\).

Which of the above statements are true? Give the answer as the product of serial numbers of the right options. For ex. If 1 and 4 are correct the answer should be 1×4=4.

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