# Give it a try

Let $$f(n)$$ be a function defined on the non-negative integers given the following facts:

• $$f(0)=f(1)=0$$.

• $$f(2)=1$$

• For $$n>2$$, $$f(n)$$ gives the smallest positive integer, which does not divide $$n$$.

Let $$g(n)=f(f(f(n)))$$, find $$g(1)+g(2)+g(3)+\cdots+g(2016)$$.

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