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sin6(θ)+cos6(θ)=sin(2θ)= ?\large \sin^{6}(\theta)+\cos^{6}(\theta)=\sin(2\theta) = \ ? sin6(θ)+cos6(θ)=sin(2θ)= ?
If the above equation is true, then what is the value of sin(2θ)\sin(2\theta)sin(2θ)? Give your answer to 3 decimal places.
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