Gravity is back again!

The acceleration due to gravity on Moon(\(g_m\)) is \(\frac16\) that of Earth(\(g_e\)) and the radius of the Moon(\(R_m\))is \(\frac14\) that of Earth(\(R_e\)). Find the escape velocity of Moon in terms of escape velocity of Earth.

The answer is in the from \(\dfrac{v_e}{\sqrt{\overline{ab}}}\) where \(\overline{ab}\) is a two digit number, find \(a^b\).

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