If we square the equation, \(x + \dfrac1x = 3 \), we get

\[\begin{eqnarray} \left( x + \dfrac1x \right)^2 &=& 3^2 \\ x^2 + \dfrac1{x^2} + 2 &=& 9 \\ x^2 + \dfrac1{x^2} &=& 7 \end{eqnarray} \]

What is the value of the \(x^4 + \dfrac1{x^4} \)?

**Hint**: Try squaring the equation again!

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