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If α,β\alpha,\betaα,β are the roots of the quadratic equation
x2−(3+2log23−3log32)x−2(3log32−2log23)=0x^2-\left( 3+2^{\sqrt{\log_23}}-3^{\sqrt{\log_32}} \right)x-2\left( 3^{\log_32}-2^{\log_23} \right) =0x2−(3+2log23−3log32)x−2(3log32−2log23)=0,
then find the value of (α2+αβ+β2)\left( \alpha^2+\alpha\beta+\beta^2 \right) (α2+αβ+β2).
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