# Height Problem 2

**Algebra**Level 3

R is 156 cm tall.S is one sixth \(\times \)8 of R. P is \(\cfrac { 1 }{ 4 } th\) of S \(\times \) \(\cfrac { 5 }{ 2 } \).And Q is \(\cfrac { 1 }{ 5 } th\quad\)of P \(\times \quad 4\)

Then add their heights , add 2 in that addition , and then square the solution after adding 2, and write the answer.