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1⌊x⌋+1⌊2x⌋={9x}+13\large \frac 1{\lfloor x \rfloor} + \frac 1{\lfloor 2 x \rfloor} = \{ 9x \} + \frac 13 ⌊x⌋1+⌊2x⌋1={9x}+31
If the smallest positive solution of xxx satisfying the equation above is of the form mn\frac {m}{n}nm, where mmm and nnn are coprime positive integers, find m−nm-nm−n.
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