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limn→∞ln(n∫01(x+2016x2n)n dx)= ?\large \lim _{ n\rightarrow \infty }{ \ln\left( n\int _{ 0 }^{ 1 }{ { \left( x+\frac { { 2016x }^{ 2 } }{ n } \right) }^{ n } \, dx } \right) } = \, ? n→∞limln(n∫01(x+n2016x2)ndx)=?
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