# How Many Antiderivatives Are There?

Calculus Level 1

True or false:

By double angle identities, we know that $$\cos2x = 2\cos^2x - 1 = 1-2\sin^2 x$$.

$\begin{eqnarray} \int 2\sin 2x \, dx &=& -\cos 2x + C \\ &=&- 2\cos^2x + 1 + C \\ &=& - 2\cos^2x + C \end{eqnarray}$

$\begin{eqnarray} \int 2\sin 2x \, dx &=& -\cos 2x + C \\ &=& -1 + 2\sin^2 x + C \\ &=& 2\sin ^2x + C \end{eqnarray}$

From the two indefinite integrals below, we can see that $- 2\cos^2x + C = 2\sin ^2x + C \; .$

Cancelling off the arbitrary constant of integration $$C$$, we obtain $$-2\cos^2 x = 2\sin^2x$$ or equivalently $$\cos^2 x =- \sin^2 x$$ is true for all $$x$$.

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