How many black holes can fit on the head of a pin?

Black holes are regions of space from which nothing can escape. If you consider a spherical object of mass M and radius R and set the escape velocity from the object to be $c$, the speed of light, you can determine a relationship between R and M, $R=2 GM/c^2$, where $G$ is Newton's gravitational constant. This radius is called the Schwarzschild radius, denoted by $R_s$. If mass M is concentrated into a region with a radius smaller than $R_s$ then you have a black hole, and if not, there is no black hole.

From the above relation you can determine the minimum mass of a black hole, as roughly speaking the Schwarzschild radius must be larger or equal to the Compton wavelength - the minimum size of the region in which an object at rest can be localized.

Find the minimum mass of a black hole in $\mu g$.

Finally, a bonus thing to think about. What does this result mean for the masses of the particles that we see in nature?

Details and assumptions

• The value of the gravitational constant is $G=6.67 \times 10^{-11} \text{ m}^3\text{/kg s}^2$.
• The speed of light is $c=3 \times 10^8\text{ m/s}$.
• Planck's constant is $h=6.63 \times 10^{-34} \text{ kgm}^2\text{/s}$.
• $1 ~\mu g = 10^{-6} \text{ g} = 10^{-9} \text{ kg}$