\[2\sqrt[4x]{x^{3x}} = 3\sqrt[2x]{x^{4x}}\]

Find the real value of \(x\) satisfying the equation above.

The answer is of the form \(\sqrt[5]{\dfrac{a}{b}}\) where \(a\) and \(b\) are positive co-prime integers, then submit the value of \(a + b\).

\(\text{Note}\):- Here \(x \neq -1,0,1\)

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