$2\sqrt[4x]{x^{3x}} = 3\sqrt[2x]{x^{4x}}$

Find the real value of $x$ satisfying the equation above.

The answer is of the form $\sqrt[5]{\dfrac{a}{b}}$ where $a$ and $b$ are positive co-prime integers, then submit the value of $a + b$.

$\text{Note}$:- Here $x \neq -1,0,1$