# How would you solve it: Part 4

Calculus Level 5

$\large \displaystyle \sum_{n=0}^{\infty}\dfrac{(-1)^{n}}{n+1}{2n \choose n}^{-1} = \dfrac{\alpha}{\sqrt{\beta}}\ln^{\eta}{\phi} - \delta(\ln^{\gamma}{\phi})$ If the above summation is true for positive integers: $$\alpha,\beta,\gamma,\delta,\eta$$ and that $$\beta$$ is a prime, then compute: $\alpha+\beta+\gamma+\delta+\eta$.
Note that: $$\phi$$ is the Golden ratio
This is $$95$$ % Original

×