Forgot password? New user? Sign up
Existing user? Log in
DDD lies on segment BCBCBC, CECECE is tangent to circumcircle ⊙ABD\odot ABD⊙ABD at EEE, and ∠CAD=∠BCE\angle CAD=\angle BCE∠CAD=∠BCE.
If 53BC=AC+AB\frac {5}{3}BC=AC+AB35BC=AC+AB and AC=33AC=33AC=33. Find CDCDCD.
Problem Loading...
Note Loading...
Set Loading...