# I challenge you to bash this

Geometry Level 5

Inside $$\triangle ABC$$ lies a point $$P$$ satisfying $$\angle CAP=15^{\circ}$$. Let $$Q$$ be another point inside the triangle such that $$\angle QCB=\angle ACP,\angle QBC=\angle ABP$$. Suppose the circumcenter of $$ABC$$ lies on $$QP$$ and $$\angle A=55^{\circ}$$, find $$\angle PCB+\angle QBC$$ in degrees.

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