I challenge you to bash this

Geometry Level 5

Inside \(\triangle ABC\) lies a point \(P\) satisfying \(\angle CAP=15^{\circ}\). Let \(Q\) be another point inside the triangle such that \(\angle QCB=\angle ACP,\angle QBC=\angle ABP\). Suppose the circumcenter of \(ABC\) lies on \(QP\) and \(\angle A=55^{\circ}\), find \(\angle PCB+\angle QBC\) in degrees.

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