I haven't seen it before 2

Calculus Level 5

Let Pn=1n+13n3+15n5+17n7+ \mathfrak P_n=\dfrac 1n+\dfrac{1}{3n^3}+\dfrac{1}{5n^5}+\dfrac{1}{7n^7} + \cdots.

If the value of n=2992Pn\displaystyle\sum_{n=2}^{99} 2\mathfrak{P}_n is equal to lnα \ln\alpha, find α\alpha.


Try the Part-1 here.
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