I Thought It Adds Up To 180?

Geometry Level 2

sinABC=sin137sinBAC=sin76sinACB=sin61  \begin{array} {l l } \sin{\angle ABC}& =\sin{137^{\circ}} \\ \sin{\angle BAC}& =\sin{76^{\circ}} \\ \sin{\angle ACB}& =\sin{61^{\circ}}\ \end{array}

Is it possible to have a ABC\triangle ABC satisfying the conditions above?

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