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sin∠ABC=sin137∘sin∠BAC=sin76∘sin∠ACB=sin61∘ \begin{array} {l l } \sin{\angle ABC}& =\sin{137^{\circ}} \\ \sin{\angle BAC}& =\sin{76^{\circ}} \\ \sin{\angle ACB}& =\sin{61^{\circ}}\ \end{array} sin∠ABCsin∠BACsin∠ACB=sin137∘=sin76∘=sin61∘
Is it possible to have a △ABC\triangle ABC△ABC satisfying the conditions above?
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