# I won't possibly throw like that, would I?

Ball $$A$$ of mass $$1\text{ kg}$$ is thrown at an angle of $${45}^\circ$$ with the horizontal with kinetic energy $$50\text{ J}$$ such that it hits ball $$B$$ of the same mass placed on the top of a pole. In this collision, half of the kinetic energy of ball $$A$$ at that instant is transferred to ball $$B,$$ causing ball $$B$$ to move in a forward direction. If it is known that the height at which ball $$B$$ was placed is the maximum height that the initial projectile of ball $$A$$ would have traveled, then find the distance of the final position of ball $$B$$ from the foot of the pole.

The figure below would help in understanding the situation:

Details and Assumptions:

• Ball $$B$$ does not rebound after hitting the ground.
• Air friction is negligible.
• Take $$g=10\text{ m/s}^2$$ as the acceleration due to gravity.
• Give your answer (in $$\text{m}$$) to two decimal places.
×