IIT JEE Problem

Calculus Level 4

Thevalueof01x4(1x)41+x2dxis:The\quad value\quad of\quad \int _{ 0 }^{ 1 }{ \frac { { x }^{ 4 }{ (1-x) }^{ 4 } }{ 1+{ x }^{ 2 } } } dx\quad is:

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