I'm stuck! Retrieve me! Try this
\(ABC\) is a right triangle angle \(A=63^\circ\), angle \(B=27^\circ\). \(ACFG\) and \(BCDE\) are squares drawn external to the triangle \(ABC\) such that \(AE\) intersect \(BC\) at \(h\) and \(BG\) intersect \(AC\) at \(K\). Then find \( \angle DKH \).
Clarifications: All angles in terms of degrees.