Tricky 2015 Sum

Calculus Level 3

n=0120152n2015(2n)\displaystyle\sum_{n=0}^{\infty} \dfrac{1}{2015^{2^{n}} - 2015^{-(2^{n})}}

If the closed form of the series above is in the form ab \frac a b , where aa and bb are positive coprime integers, then find ba.b - a.

×

Problem Loading...

Note Loading...

Set Loading...