At \(6[m]\) from the floor a mass \(5[kg]\) is dropped on a inclined plane which form an angle \(\theta\) with the horizontal. If the base of the inclined plane is \(8[m]\) long, and the coefficient of friction of the mass with the inclined plane is \(0,6\), what is the **absolute value** of the work (in Joules) done by the friction force untill the mass get to the floor?

Details and Assumptions:

- Take \(g=10[\frac{m}{s^2}]\)

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