At \(6[m]\) from the floor a mass \(5[kg]\) is dropped on a inclined plane which form an angle \(\theta\) with the horizontal. If the base of the inclined plane is \(8[m]\) long, and the coefficient of friction of the mass with the inclined plane is \(0,6\), what is the absolute value of the work (in Joules) done by the friction force untill the mass get to the floor?

Details and Assumptions:

- Take \(g=10[\frac{m}{s^2}]\)

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