Two capacitors of capacitances \(C_1\) and \(C_2\) are connected in series with an inductor of inductance \(L\). Initially the capacitors have charge such that \(V_B-V_A=4V_0\) across \(C_1\) and \(V_C-V_D=V_0\) across \(C_2\). Now if

a) Maximum current in circuit is \(\xi\).

b) Potential drop across \(C_1\) is \(\mu\) at that instant.

c) Potential drop across \(C_2\) is \(\eta\) at that instant.

d) Equation of current flowing towards left in the inductor is given by \(i= \psi \left( \sin { \left( \frac { \omega t }{ \varsigma } \right) } \right) \).

Find \( \xi +\mu +\eta +\psi +\omega +\varsigma\).

**Details And Assumptions:**

\(C_0=2F\)

\(L=\dfrac 13 \ H\)

\(V_0=4 \ \text{volt}\)

Initially the current in the circuit is zero.

\(\omega\) and \(\varsigma\) are co-prime.

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