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(1+23+1)(1+232+1)(1+233+1)⋯= ?\left (1+\frac { 2 }{ 3+1 } \right)\left (1+\frac { 2 }{ { 3 }^{ 2 }+1 } \right)\left (1+\frac { 2 }{ { 3 }^{ 3 }+1 } \right) \cdots = \ ? (1+3+12)(1+32+12)(1+33+12)⋯= ?
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