Infinity and Beyond

Calculus Level 4

\[ \sum_{n=1}^\infty \dfrac{n(n+1)}{2^{n-1}} = 2+3+\frac{12}{4}+\frac{20}{8}+\frac{30}{16}+\frac{42}{32}+\frac{56}{64}+\cdots\]

Compute the sum above.

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