\[\large{{ a }_{ n+1 }={ a }_{ n }-{\left\lfloor \sqrt { { a }_{ n } } \right\rfloor}}^{2} \]

Let there be a sequence for \(n \ge 1\). For \(n \ge k\), the value of \(a_{n}\) will be \(0\) for some positive integer \(k\). If \(k=9\) find \(a_{1}\).

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