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∑μ(n)=11n2=ABπC\sum_{\mu(n)=1} \frac{1}{n^2} = \frac{A}{B\pi^C}μ(n)=1∑n21=BπCA
Let μ(n)\mu(n)μ(n) denote the möbius function, the sum is taken over all positive integers nnn such that μ(n)=1\mu(n)=1μ(n)=1, with coprime positive integers AAA and B.B.B. Find A+B+CA+B+CA+B+C.
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