# Inspired by Nihar and Sandeep

When a non-negative integer $$x$$ is divided by 5, we get a remainder $$y$$ such that the number $$x$$ can be represented as $$x=q×5+y$$. For an explicit example if $$x=41$$, then we have $$x=8×5+1$$. And note that the remainder, here, is 1.

If I give you three chances to enter the integer $$y$$, what is the probability that you will get the qu​estion right on the third attempt?

Clarification:

• You will have to come up with a valid option (a possible remainder which we get after division by 5) each time you enter an integer.

• The remainder is defined being bounded in the interval $$[0, 5)$$

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