Forgot password? New user? Sign up
Existing user? Log in
p3a+1+pa+1=bp\large p^{3a+1}+p^a+1=b^pp3a+1+pa+1=bp
Find all solutions to the Diophantine equation above, where aaa and bbb are positive integers and ppp is an odd prime, and enter your answer as ∑(a+b+p)\sum (a+b+p)∑(a+b+p).
Problem Loading...
Note Loading...
Set Loading...