Inspired by Sanyog Ghosh

Algebra Level pending

$\large \displaystyle \left ( \sum_{n=1}^{ 10^{\lfloor \pi \rfloor} + 9^{\lceil e \rceil} } (-1)^{n+1} \times \lceil \sqrt [3]{n} \rceil^{2} \right ) - 7^{2} = \ ?$

Notes:

• $$\lfloor \alpha \rfloor$$ is the floor function

• $$\lceil \alpha \rceil$$ is the ceiling function

• $$e$$ is Euler's number

• $$\pi$$ is pi

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