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tan(x+120∘)tan(x−30∘)=112 \dfrac{\tan(x + 120^{\circ})}{\tan(x - 30^{\circ})} = \dfrac{11}{2}tan(x−30∘)tan(x+120∘)=211
If xxx is a solution to the above equation and cos(4x)=ab,\cos(4x) = \dfrac{a}{b},cos(4x)=ba, where aaa and bbb are coprime positive integers, then find a+b.a + b.a+b.
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