# INTEGER TYPE -2

**Geometry**Level pending

Three points P(a,b) ,Q(c,d) and R(e,f) satisfy the inequality \(x^2\)+\(y^2\) -6x-8y < 0 such that 'P' lies at a least distance from A(-2,4) and Q and R lies at maximum distance from A , where a,b,c,d,e and f are integers. The internal bisector of P of triangle PQR intersects the tangent at origin and the point ( \(\frac{c+e}{2}\)+1,d) to the circle \(x^2\) +\(y^2\) -6x-8y=0 . If the area of Triangle formed by these three lines is T , then \(\frac{3T}{50}\) is equal to ?

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