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f(x)={0 if x is rational1 if x is irrational f(x)=\begin{cases} 0\text{ if } x\text{ is rational}\\\\ 1\text{ if }x\text{ is irrational} \end{cases}f(x)=⎩⎪⎨⎪⎧0 if x is rational1 if x is irrational
Is the function above Riemann integrable on [0,1]?[0,1]?[0,1]? Is it Lebesgue integrable on [0,1]?[0,1]?[0,1]?
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