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The equation limx→0∫0xt2dt(x−sinx)a+t=1 \displaystyle \lim_{x \to 0} \int_0^x \frac {t^2 \mathrm d t}{(x- \sin x) \sqrt{a+t} } = 1 x→0lim∫0x(x−sinx)a+tt2dt=1 is true for a constant aaa.
What is the value of a?a?a?
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